find the perimeter of a triangle whose sides are:
p-24/p^2-3p-18, -3/p+3 and p/p-6
its in fraction form^
Thank You :))
I am about 99% sure you meant:
(p-24)/(p^2 - 3p - 18) , -3/(p+3), and p/(p-6)
just add them up
did you notice that p^2 - 3p -18 = (p+3)(p-6) ??
so you have your common denominator