Horse canters away from its trainer in a straight line moving 130 m away in 16.0 s. It then turns abruptly and gallops halfway back in 4.3 s?

(a) Calculate its average speed.

(b) Calculate its average velocity for the entire trip, using "away from the trainer" as the positive direction.

speed: (130+65)m/(16.0+4.3)s = 9.61 m/s

velocity: (130-65)m/(16.0+4.3)s = 3.20 m/s

(a) Well, it seems like the horse really wanted to stretch its legs! To calculate its average speed, we can use the formula speed = distance ÷ time. The horse traveled a total distance of 130m away from its trainer in a total time of 16.0s. So, let's do the math: speed = 130m ÷ 16.0s.

Oh dear, the horse is really fast! Its average speed is approximately 8.125 m/s.

(b) Now, to calculate the average velocity, we need to take into account the direction. Since we are considering "away from the trainer" as the positive direction, we need to use positive and negative signs to indicate direction. The horse moved 130m away from its trainer, and then halfway back. So the total displacement is 130m - 65m, which is 65m away from its initial position.

The total time for the trip is 16.0s + 4.3s, which is 20.3s.

To calculate the average velocity, we use the formula velocity = displacement ÷ time. Plugging in the values, we get velocity = 65m ÷ 20.3s.

So, the average velocity of the horse is approximately 3.201 m/s away from its trainer, taking into account the positive direction.

Remember, my calculations are quite "horsing around," so take them with a pinch of salt!

To calculate the average speed of the horse, you need to divide the total distance traveled by the total time taken.

(a) Average speed = Total distance / Total time

In this case, the horse moved 130 meters away from its trainer in 16.0 seconds. Therefore, the total distance traveled is 130 meters, and the total time taken is 16.0 seconds.

Average speed = 130 m / 16.0 s = 8.125 m/s

So, the average speed of the horse is 8.125 m/s.

(b) To calculate the average velocity for the entire trip, we need to consider both the direction and the displacement.

Since the horse moved away from the trainer as the positive direction, we will consider it positive.

First, let's calculate the displacement during the first phase of the movement. The horse moved 130 meters away from the trainer, so the displacement is +130 meters.

Next, we need to calculate the displacement during the second phase. The horse galloped halfway back, which is a displacement of -65 meters since it is moving in the opposite direction.

To calculate the average velocity, we need to sum up the displacements and divide by the total time taken.

Total displacement = +130 m + (-65 m) = +65 m

Total time taken = 16.0 s + 4.3 s = 20.3 s

Average velocity = Total displacement / Total time taken

Average velocity = 65 m / 20.3 s = 3.2 m/s (approximately)

So, the average velocity of the horse for the entire trip, using "away from the trainer" as the positive direction, is 3.2 m/s (approximately).

Wrong

B

in my opinion.