Calculus

Finding critical numbers

g(theta) = 16(theta) - 4tan(theta)

I can only get the derivative of g to be g'(theta) = 16 - 4sec^2(theta).
Am I supposed to move on to get sec^2(theta) = 4, then sec(theta) = 2?

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asked by Justin
  1. g(Ø) = 16Ø - 4tanØ
    g ' (Ø) = 16 - 4sec^2 Ø
    = 0

    4sec^2 Ø = 16
    sec^2 Ø = 4
    secØ = ±2

    cosØ = ± 1/2
    we know cos 60° or cos π/3 = 1/2 , and because of the ± , Ø could be in any of the four quadrants

    Ø = 60° or 120° or 240° or 300°
    or
    Ø = π/3, 2π/3 , 4π/3 , 5π/3

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    posted by Reiny

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