Write the dissociation equation for iron(II) ammonium sulfate hexahydrate in water .
Fe(NH4)2(SO4)2 * 6H2O --> __?________
I know dissociate means to take apart so for example; NaCl would look like Na^+ + Cl^-
And another one like: Fe2(SO4)3 would look like 2Fe^+3 + 3SO4^-2 but I can't seem to figure out how (the question above) would look like when it is dissociated. Can you please explain step by step on how to get the answer for my problem? Thank you so much! All help needed!
The ammoniated iron (Fe(NH4)++) will dissociate from the sulfate iron, and of course the hydrated complex will be standing alone.
To determine the dissociation equation for iron(II) ammonium sulfate hexahydrate, we need to break down the compound into its individual ions when it dissociates in water. Here's how you can do it step by step:
Step 1: Identify the ions present in the compound:
The compound is Fe(NH4)2(SO4)2 * 6H2O. From this, we can determine the following ions:
- Iron(II) ion (Fe2+)
- Ammonium ion (NH4+)
- Sulfate ion (SO42-)
- Water molecule (H2O)
Step 2: Determine the number of each ion in the formula:
Fe(NH4)2(SO4)2 * 6H2O contains one Fe2+ ion, two NH4+ ions, two SO42- ions, and six H2O molecules.
Step 3: Write the dissociation equation:
To dissociate the compound, we write it as separate ions:
- Fe(NH4)2(SO4)2 * 6H2O dissociates into Fe2+ ions, NH4+ ions, SO42- ions, and H2O molecules.
The dissociation equation can be written as follows:
Fe(NH4)2(SO4)2 * 6H2O -> Fe2+ + 2NH4+ + 2SO42- + 6H2O
So, the dissociation equation for iron(II) ammonium sulfate hexahydrate in water is:
Fe(NH4)2(SO4)2 * 6H2O -> Fe2+ + 2NH4+ + 2SO42- + 6H2O
Note: This equation represents the dissociation of the compound into its respective ions when dissolved in water.
To determine the dissociation equation for iron(II) ammonium sulfate hexahydrate (Fe(NH4)2(SO4)2 * 6H2O) in water, we will break down each component of the compound and separate them into their respective ions.
First, let's analyze each ion in the compound:
- The iron(II) ion (Fe^2+) will dissociate as Fe^2+.
- The ammonium ion (NH4^+) will dissociate as NH4^+.
- The sulfate ion (SO4^2-) will dissociate as SO4^2-.
- The water molecules (H2O) do not typically dissociate in this scenario, so they will remain as water.
Now, let's write the dissociation equation, taking into account the number of each ion present in the compound:
Fe(NH4)2(SO4)2 * 6H2O -> [Fe^2+] + 2[NH4^+] + 2[SO4^2-] + 6[H2O]
This equation represents the dissociation of one formula unit of iron(II) ammonium sulfate hexahydrate into its respective ions. The coefficients in front of each ion represent the number of that ion released upon dissociation.
Please note that in reality, not all ionic compounds readily dissociate completely in water, and the degree of dissociation may vary. This equation assumes complete dissociation for the sake of simplicity.