You place a piece of paper on a balance and find that its mass is 0.63 g. You add a lump of NaOH to the paper and get a mass of 22.21 g. You remember that you forgot to tare the balance before taking this measurement. You tare the balance, add another lump of NaOH, and read 20.64 g. You add another lump of NaOH and read 38.98 g. How Much NaOH do you have on the balance, in grams, milligrams, micrograms and kilograms?
To determine the mass of NaOH on the balance, we need to subtract the mass of the paper from each measurement. Let's break down the steps:
1. Initial measurement:
- Mass of paper + NaOH = 22.21 g
- Mass of paper = 0.63 g
- Mass of NaOH = 22.21 g - 0.63 g = 21.58 g
2. Second measurement (after taring the balance):
- Mass of paper + NaOH = 20.64 g
- Mass of paper = 0.63 g
- Mass of NaOH = 20.64 g - 0.63 g = 20.01 g
3. Third measurement:
- Mass of paper + NaOH = 38.98 g
- Mass of paper = 0.63 g
- Mass of NaOH = 38.98 g - 0.63 g = 38.35 g
Now, let's convert these measurements to other units:
1. Mass of NaOH in grams:
- First measurement: 21.58 g
- Second measurement: 20.01 g
- Third measurement: 38.35 g
2. Mass of NaOH in milligrams (1 g = 1000 mg):
- First measurement: 21.58 g * 1000 mg/g = 21580 mg
- Second measurement: 20.01 g * 1000 mg/g = 20010 mg
- Third measurement: 38.35 g * 1000 mg/g = 38350 mg
3. Mass of NaOH in micrograms (1 mg = 1000 µg):
- First measurement: 21580 mg * 1000 µg/mg = 21580000 µg
- Second measurement: 20010 mg * 1000 µg/mg = 20010000 µg
- Third measurement: 38350 mg * 1000 µg/mg = 38350000 µg
4. Mass of NaOH in kilograms (1 g = 0.001 kg):
- First measurement: 21.58 g * 0.001 kg/g = 0.02158 kg
- Second measurement: 20.01 g * 0.001 kg/g = 0.02001 kg
- Third measurement: 38.35 g * 0.001 kg/g = 0.03835 kg
Therefore, the mass of NaOH on the balance is:
- In grams: 21.58 g, 20.01 g, 38.35 g
- In milligrams: 21580 mg, 20010 mg, 38350 mg
- In micrograms: 21580000 µg, 20010000 µg, 38350000 µg
- In kilograms: 0.02158 kg, 0.02001 kg, 0.03835 kg