calculate the ratio of momentrum when (a) velocity of an object is doubled (b) mass of an object is halved (c) both mass and velocity are increased by three times
See previous post: Sat, 10-3-15, 12:51
PM.
Batao
prove that f=π√coa.sinm/12.45
To calculate the ratio of momentum in different scenarios, we'll use the formula for momentum:
Momentum = mass × velocity
Let's calculate each scenario step by step:
(a) When the velocity of an object is doubled:
In this case, only the velocity changes, while the mass remains constant. Let's assume the initial velocity is V and the mass is M.
The new velocity would be 2V.
So, the ratio of momentum in this scenario would be:
(Mass × New Velocity) / (Mass × Initial Velocity) = (M × 2V) / (M × V) = 2V / V = 2.
Therefore, the ratio of momentum is 2.
(b) When the mass of an object is halved:
In this scenario, only the mass changes, while the velocity stays the same. Let's assume the initial mass is M and the velocity is V.
The new mass would be M/2.
So, the ratio of momentum in this case would be:
(New Mass × Velocity) / (Initial Mass × Velocity) = ((M/2) × V) / (M × V) = (1/2M) / (M) = 1/2.
Therefore, the ratio of momentum is 1/2 or 0.5.
(c) When both mass and velocity are increased by three times:
In this situation, both mass and velocity change. Let's assume the initial mass is M, and the initial velocity is V.
The new mass would be 3M, and the new velocity would be 3V.
So, the ratio of momentum in this case would be:
(New Mass × New Velocity) / (Initial Mass × Initial Velocity) = ((3M) × (3V)) / (M × V) = 9MV / MV = 9.
Therefore, the ratio of momentum is 9.
To summarize, the ratios of momentum in the given scenarios are:
(a) 2 (when velocity is doubled)
(b) 0.5 or 1/2 (when mass is halved)
(c) 9 (when both mass and velocity are increased by three times)