I made a mistake in my problem . can you take me step by step on how to solve this problem

2x+3y=6 (forx)

2x+3y=6 (forx) (subtract 3y to both sides)
2x=6-3y (divide both sides by 2)
x=3-3/2y

This what I got.

To solve the equation 2x + 3y = 6 for x, here are the steps:

1. Start with the equation: 2x + 3y = 6.
2. To solve for x, you want to isolate x on one side of the equation.
3. To do this, first subtract 3y from both sides of the equation to get rid of the term that contains y:
2x = 6 - 3y.
4. Now, you have 2x isolated on the left side of the equation.
5. To further isolate x, divide both sides of the equation by 2:
x = (6 - 3y) / 2.
6. Simplify the right side of the equation if necessary.
In this case, you can distribute the division by 2 to both terms inside the parentheses:
x = 6/2 - (3/2)y.
Simplifying the expression gives:
x = 3 - (3/2)y.

So, the correct solution for x in the equation 2x + 3y = 6 is x = 3 - (3/2)y.