a mango fruit drops to the ground from the top of its tree which is 5m high.how long does it take to reach the ground?
well, in t seconds it falls 4.9t^2 meters.
Looks like t≈1
To determine how long it takes for the mango fruit to reach the ground, we can use the equations of motion. Specifically, we can utilize the equation for falling objects under gravity:
h = (1/2) * g * t^2
Where:
- h is the height of the object (5m in this case)
- g is the acceleration due to gravity (approximately 9.8 m/s^2 on Earth)
- t is the time taken for the object to fall
To find the time, rearrange the equation to solve for t:
t = sqrt((2 * h) / g)
Substituting the given values:
t = sqrt((2 * 5) / 9.8)
t = sqrt(10 / 9.8)
t = sqrt(1.020408163265306)
t ≈ 1.01 seconds
Therefore, it takes approximately 1.01 seconds for the mango fruit to reach the ground.