diameter of the atomic nucleus of a lead atom is 1.75 x 10^-10
cool. pretty small, eh?
To find the diameter of the atomic nucleus of a lead atom, we can use the given information that the diameter is 1.75 x 10^-10 (in meters).
The diameter of a sphere, such as the atomic nucleus, is twice the radius. Therefore, we can find the radius by dividing the given diameter by 2.
diameter = 1.75 x 10^-10
radius = (1.75 x 10^-10) / 2
Let's calculate the radius of the atomic nucleus:
radius = (1.75 x 10^-10) / 2
= 8.75 x 10^-11 meters
So, the radius of the atomic nucleus of a lead atom is approximately 8.75 x 10^-11 meters.