Probability license Arrangements

All license plates have a letter, two characters (which are either a number or a letter) Followed by two numbers. The letter choice for the first character can only be either an E,W,P,R,A,F OR U. How many license plates can be made? What is the probability of having one with a vowel?

asked by Amber
  1. so a possible valid choice could be R 2S 56

    All cases = 7 x 36 x 36 x 10 x 10907200
    Assuming 5 vowels
    number of cases without a vowel
    = 4 x 31 x 31 x 10 x 10 = 3844400

    prob(of having a vowel) = 1 - 384400/1090700
    = appr .576

    check my arithmetic

    posted by Reiny
  2. Found a typo .... forgot the = sign

    should be :

    All cases = 7 x 36 x 36 x 10 x 10 = 907200

    posted by Reiny

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