Not Urgent But Please Check My Answer:

A pencil at a stationery store costs $1, and a pen costs $1.50. Stella spent $21 at the store. She bought a total of 18 items. Which system of equations can be used to find the number of pencils (x) and pens (y) she bought?

I think it is this: x + 18y = 21
x = 1.5y

18x + y = 21
x = 1.5y

x + 1.5y = 21
x + y = 18

I know for a fact not this: 1.5x + y = 21
x = 18y

OR if you write :

x = number of pencils

y = number of pens

then

x + 1.5 y = 21

x + y = 18

x = number of pens

y = number of pencils

She bought a total of 18 items.

x + y = 18

Stella spent 21 $

1.5$ * x + 1 $ * y = 21 &

1.5 x + 1 * y = 21

1.5 x + y = 21

You must solve system :

x + y = 18

1.5 x + y = 21

The solutions aree .

x = 6

y = 12

Proof :

6 * 1.5 $ + 12 * 1 $ = 9 $ + 12 $ = 21 $

Your answer is partially correct. The correct system of equations to find the number of pencils (x) and pens (y) she bought is:

x + y = 18
1x + 1.5y = 21

This is because she bought a total of 18 items (x + y = 18) and spent $21 (1x + 1.5y = 21), with x representing the number of pencils and y representing the number of pens.

To solve this problem, we can set up a system of equations based on the given information.

Let's assume that she bought x number of pencils and y number of pens.

1. We know that the cost of each pencil is $1, so the total cost of pencils would be x * $1 = $x.
2. Similarly, the cost of each pen is $1.50, so the total cost of pens would be y * $1.50 = $1.5y.

From the given information, we also know:
1. Stella spent a total of $21, so the equation for the total cost would be: $x + $1.5y = $21.
2. Stella bought a total of 18 items, so the equation for the total number of items would be: x + y = 18.

Therefore, the correct system of equations to solve for the number of pencils (x) and pens (y) would be:

Equation 1: x + y = 18
Equation 2: x + 1.5y = 21

So, the correct option is:
x + y = 18
x + 1.5y = 21

You can solve this system of equations using different methods like substitution, elimination, or graphing to find the values of x and y.