A basketball player is 6 ft. 4 in. tall and a volleyball player who is 1.75 m.
17. How tall is the basketball player in meters? How tall is the volleyball player in feet? (round to one decimal place)
1 ft = 12 in
6 ft 4 in = 6 * 12 + 4 = 72 + 4 = 76 in
1 in = 2.54 cm = 2.54 / 100 = 0.0254 m
Tall of the basketball player in meters :
76 * 0.0254 = 1.9304 m
Tall of the volleyball player in feet :
1.75 / 0.0254 = 68.89763778 ft =
68.9 in rounded to one decimal place
68.9 ft rounded to one decimal place
Look up the conversion factor for feet-to-meters. Then multiply that by 19/3.
Well, if I were to stretch my comedic muscles, I'd say that the basketball player is about 2 meters tall because, you know, he can slam dunk in both feet.
As for the volleyball player, they are approximately 5 feet 9 inches tall. I don't know if they can dunk, but they definitely have a good "set" of skills.
To convert the height of the basketball player from feet and inches to meters, we need to first convert the height to inches, and then divide by the conversion factor from inches to meters.
1 foot is equal to 12 inches, so the height of the basketball player in inches is:
6 ft * 12 in/ft + 4 in = 72 in + 4 in = 76 in
Now, we can convert inches to meters. The conversion factor is 0.0254 meters/inch.
Height in meters = (Height in inches) * (0.0254 meters/inch)
Height in meters = 76 in * 0.0254 meters/inch
Height in meters ≈ 1.93 meters (rounded to two decimal places)
Therefore, the basketball player's height in meters is approximately 1.93 meters.
To convert the height of the volleyball player from meters to feet, we need to multiply the height in meters by the conversion factor from meters to feet.
1 meter is equal to 3.281 feet, so the height of the volleyball player in feet is:
1.75 m * 3.281 ft/m = 5.74 ft (rounded to two decimal places)
Therefore, the volleyball player's height in feet is approximately 5.74 feet.