1\8(3d-2)=1/4(d+5)
1/8 (3d-2) = 2/8 (d+5)
3d-2 = 2(d+5)
can you take it from there?
How did you get 2/8's
Oh, please!
Surely you know that 1/4 = 2/8!
If not, you have no business taking algebra.
To solve the equation 1/8(3d-2) = 1/4(d+5), we need to eliminate the denominators by multiplying both sides of the equation by the least common denominator (LCD), which is 8.
Step 1: Multiply both sides of the equation by 8 to eliminate the denominators:
8 * [1/8(3d-2)] = 8 * [1/4(d+5)]
This simplifies to:
3d - 2 = 2(d + 5)
Step 2: Distribute the 1/8 and 1/4 to the terms inside the parentheses:
(3/8)d - 1/4 = (1/2)d + (5/2)
Step 3: Group the "d" terms on one side and the constant terms on the other side of the equation:
(3/8)d - (1/2)d = (5/2) + (1/4)
This simplifies to:
[(3/8) - (1/2)]d = (10/4) + (1/4)
Step 4: Combine like terms:
[(3/8) - (4/8)]d = (11/4)
This simplifies to:
(-1/8)d = (11/4)
Step 5: Multiply both sides of the equation by the reciprocal of -1/8, which is -8/1 to solve for "d":
(-1/8)d × (-8/1) = (11/4) × (-8/1)
This simplifies to:
d = (-88/4)
Step 6: Simplify the fraction (-88/4):
d = -22
Therefore, the solution to the equation 1/8(3d-2) = 1/4(d+5) is d = -22.