If 20g of CaCo3is treated with 20gm of HCl how many grams of CO2 can be generated CaCO3+2HCl gives CaCl+H2O+CO2
Follow your previous CaCO3 problem. Convert 20 g HCl and 20 g CaCO3 to mols first. Remember this is a limiting reagent problem.
To determine the amount of CO2 that can be generated when 20g of CaCO3 is treated with 20g of HCl, you need to use stoichiometry. Stoichiometry is used to calculate the quantitative relationships between reactants and products in a chemical reaction.
First, you need to understand the balanced equation for the reaction:
CaCO3 + 2HCl → CaCl2 + H2O + CO2
From the equation, you can see that for every 1 mole of CaCO3, 1 mole of CO2 is generated. Therefore, you need to convert the mass of CaCO3 to moles using its molar mass, and then convert the moles of CaCO3 to moles of CO2, and finally convert the moles of CO2 back to grams.
1. Calculate the moles of CaCO3:
Moles = Mass / Molar mass
Molar mass of CaCO3 = 40.08 g/mol (Ca) + 12.01 g/mol (C) + 3(16.00 g/mol) (O)
= 40.08 + 12.01 + 48.00
= 100.09 g/mol
Moles of CaCO3 = 20 g / 100.09 g/mol
2. Use the stoichiometry of the balanced equation to convert moles of CaCO3 to moles of CO2. Since the balanced equation shows a 1:1 ratio between CaCO3 and CO2, the moles of CaCO3 and moles of CO2 will be the same.
Moles of CO2 = Moles of CaCO3
3. Finally, convert moles of CO2 back to grams:
Mass = Moles of CO2 × Molar mass of CO2
= Moles of CO2 × (12.01 g/mol + 2(16.00 g/mol))
Now, you can substitute the calculated moles of CaCO3 into the equation to find the grams of CO2 that can be generated.