20,500 gallons of kerosene spill into a banked up area that measure 20 foot x 10 foot how long will the fire last it is left unattended ?
1 gallon = 3.785 liter
1000 liters = 1 m^3
1in = 2.54 cm
1ft = 12 in
The answer is approx 33 hr.
T = h / reg rate = V / A / Reg rate
Rate = 5” per hour = .127 m / hr
V = 20, 500 gallons = 77.59 m3
A = 200 ft2 = 18.61 m2
V / A / Reg Rate = 77.59 m3 / 18.61 m2 / .127 m/hr =
4.17 m / .127 m/hr = 32.83 hr.
200 foot
17 hours
To determine how long the fire will last, we need to calculate the volume of the spilled kerosene in cubic meters, and then consider various factors that affect the duration of a fire, such as the combustion rate and the heat release rate.
To calculate the volume of the spilled kerosene in cubic meters:
First, convert the gallons to liters:
20,500 gallons x 3.785 liters/gallon = 77,558.5 liters
Next, convert liters to cubic meters:
77,558.5 liters ÷ 1000 liters/m^3 = 77.5585 m^3
Now that we have the volume in cubic meters, we need to consider the combustion rate and the heat release rate, which can vary depending on several factors like the concentration of kerosene, oxygen availability, and environmental conditions.
Unfortunately, without specific information about these factors, it is not possible to provide an accurate estimate of how long the fire will last. Combustion rates can vary widely based on several variables.
If you have additional information about the combustion rate or any other relevant factors, please provide them, and I will be happy to help you further.