the difference of one more than six times a number and four more than three times the same number, using numbers 3, 5 and 7.
6x+1-3x+4=
6(3)+1-3(3)+4=
19-9+4=
19-13=6
I think you meant
(6x+1)-(3x+4) = 6x+1-3x-4 = 3x-3
using 3: 3(3)-3 = 6
Yiur asnwer was right, but your grouping of values without parentheses was wrong. As it was written, you'd have
6(3)+1-3(3)+4
multiplication comes first, unless otherwise specified using parentheses:
18+1-9+4
The addition and subtraction are done left to right:
19-9+4
10+4
14
1+1
To find the difference between one more than six times a number and four more than three times the same number, we can use the formula:
Difference = (1 + 6x) - (4 + 3x)
where x represents the number in question.
Now, let's substitute the values of 3, 5, and 7 into the formula to calculate the differences:
For x = 3:
Difference = (1 + 6(3)) - (4 + 3(3))
Difference = (1 + 18) - (4 + 9)
Difference = 19 - 13
Difference = 6
For x = 5:
Difference = (1 + 6(5)) - (4 + 3(5))
Difference = (1 + 30) - (4 + 15)
Difference = 31 - 19
Difference = 12
For x = 7:
Difference = (1 + 6(7)) - (4 + 3(7))
Difference = (1 + 42) - (4 + 21)
Difference = 43 - 25
Difference = 18
Therefore, the differences for the numbers 3, 5, and 7 are 6, 12, and 18, respectively.