An ice cube at -6 degrees Celsius increases temperature to 2 degrees celsius. If the ice cube absorbs 550 J of heat, what is the mass?
mass ice x specific heat solid ice x (Tfinal-Tinitial) = heat to move ice from -6 to zero C.
mass ice x heat fusion = heat to melt ice
mass ice x specific heat liquid water x (Tfinal-Tinitial) = heat to move T from zero C to +2 so Tfinal is +2 and Ti is 0.
The sum of each step = 550. Solve for mass ice (remember mass ice is also mass liquid water)
To find the mass (m) of the ice cube, we can use the formula Q = mcΔT, where Q is the heat absorbed or released, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.
In this case, the change in temperature (ΔT) is given as 2 degrees Celsius minus (-6) degrees Celsius, which means ΔT = 2 - (-6) = 2 + 6 = 8 degrees Celsius.
The specific heat capacity (c) for ice is approximately 2.09 J/g°C.
Next, we can rearrange the formula Q = mcΔT to solve for the mass (m).
m = Q / (cΔT)
= 550 J / (2.09 J/g°C * 8 °C)
To get the mass of the ice cube, divide the heat by the product of the specific heat capacity and the change in temperature.
m = 550 J / (2.09 J/g°C * 8 °C)
m = 550 J / (16.72 J/g)
m ≈ 32.97 g
Therefore, the mass of the ice cube is approximately 32.97 grams.