At a constant velocity, a 5kg bag of cement is pulled straight up a 7m wall. How much work is done by the puller? W(J)=F(N)*D(m)
(Gravitational pull is 9.8m/s to the second power)
W = F*d = M*g * d.
340J
343j
To calculate the work done by the puller, we need to use the formula W = F * d, where W is the work done, F is the force exerted, and d is the distance over which the force is applied.
In this case, the force being exerted on the 5kg bag of cement is equal to the weight of the bag. We can calculate the weight using the formula F = m * g, where m is the mass of the object and g is the acceleration due to gravity.
For the 5kg bag of cement, the mass (m) is given as 5kg and the acceleration due to gravity (g) is approximately 9.8m/s².
So, the force (F) exerted on the bag is:
F = m * g
F = 5kg * 9.8m/s²
F = 49N
Now, we need to find the work done by the puller in pulling the bag up the 7m wall. The distance (d) is given as 7m.
Therefore, the work done (W) is:
W = F * d
W = 49N * 7m
W = 343Nm (or Joules)
So, the puller does 343 Joules of work in pulling the 5kg bag of cement up the 7m wall.