A 41 kg child sits in a swing supported by two chains, each 1.4 m long.

If the tension in each chain at the lowest point is 261 N, find the child’s speed at the lowest point. (Neglect the mass of the seat.)

Find the force of the seat on the child at the lowest point.

To find the force of the seat on the child at the lowest point, we can use the concept of centripetal force. At the lowest point of the swing, the child is in circular motion, and the force acting towards the center of the circular path is the force of tension in the chains.

Since the forces acting on the child at the lowest point are the force of tension in the chains and the force of gravity, we can equate them to find the force of the seat on the child:

Tension in chains = Force of gravity + Force of the seat

Given that the tension in each chain is 261 N, we can set up the equation as follows:

2 * Tension in chains = mass of the child * acceleration due to gravity + Force of the seat

Substituting the given values:

2 * 261 N = 41 kg * 9.8 m/s^2 + Force of the seat

Simplifying the equation:

522 N = 401.8 N + Force of the seat

Now, we can solve for the force of the seat:

Force of the seat = 522 N - 401.8 N
= 120.2 N

Therefore, the force of the seat on the child at the lowest point is 120.2 N.