# Calculus

Let f(x)=1/x. Compute the difference quotient for f(x) at x=1 with h=0.3

I know that the formula for difference quotient is (f(x+h)-f(x))/h, but I am not sure how I am supposed to plug this in. I have tried a few ways but webworks says that the answer is wrong every time.

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1. just do what it says ...

f(x+h) , if h = .3
= f(x+.3) = 1/(x+.3)

so (f(x+h)-f(x))/h
= (1/(x+.3) - 1/x)/.3
= ((x - x - .3)/(x(x+.3))/.3
= ( -.3/(x(x-.3) )/.3
= -1/(x(x+.3))

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