There are 25 quarts of 20% anti freeze solution in the radiator of a car. How many quarts of anti freeze must be added to make a 50% anti freeze solution

The way the question stands, it makes no sense.

You would have to drain some of the solution and then add pure antifreeze.

does it ask:
How much of the current antifreeze, which is 20% , must be drained and the topped up with 100% antifreeze to have a 50% antifreeze ?

Please confirm before I answer

To find out how many quarts of anti-freeze need to be added to make a 50% solution, we need to use a basic mathematical equation. We can set up an equation using the concept of "amount of anti-freeze" (in quarts) multiplied by its concentration (in percentage).

Let's break it down step by step:

Step 1: Determine the current amount of anti-freeze in the radiator solution.
Given that there are 25 quarts of 20% anti-freeze solution, we can say that the current amount of anti-freeze in the radiator is 25 quarts multiplied by 20% = (25 * 20/100) = 5 quarts.

Step 2: Set up the equation using the unknown quantity of anti-freeze we need to add.
Let's assume we need to add "x" quarts of anti-freeze to achieve a 50% solution.

Step 3: Formulate the equation based on the anti-freeze concentrations.
The equation states that the total amount of anti-freeze after adding the new solution equals the sum of the anti-freeze before and the anti-freeze being added. In this case, we have:
(5 quarts + x quarts) = Total amount of anti-freeze in the new solution.

Step 4: Calculate the amount of anti-freeze after adding the new solution.
Since we want to have a 50% anti-freeze solution, the amount of anti-freeze in the final solution will be equal to the total volume.

Step 5: Solve the equation to find the value of x.
Now, we can solve the equation to determine the number of quarts of anti-freeze needed. Let's substitute the values in the equation:
(5 quarts + x quarts) = (25 quarts + x quarts)

To isolate "x" on one side of the equation, subtract "x" from both sides:
5 quarts = 25 quarts

Now, we can proceed to solve for "x":
x = 50 quarts

Hence, you would need to add 50 quarts of anti-freeze to the radiator to achieve a 50% anti-freeze solution.