A rectangular room is 5 meters longer than it is wide, and its perimeter is 22 meters.

a. Letting w represent the width of the rectangle, write an equation that represents the perimeter of the room. = 22

b. Find the width of the room.
The width is: meters.

c. Find the length of the room.
The length is: meters.

What don't you understand about my previous answer?

http://www.jiskha.com/display.cgi?id=1443310689

Length =11 meter

breadth=19 meter

a. The perimeter of a rectangle is equal to the sum of all its sides. In this case, we have a rectangle with a width of w and a length of w + 5. So, the equation that represents the perimeter of the room is:

Perimeter = 2 * (Width + Length)
22 = 2 * (w + (w + 5))

b. To find the width of the room, we can solve the equation derived from part a for the value of w.

22 = 2 * (2w + 5)
22 = 4w + 10
12 = 4w
w = 3

Therefore, the width of the room is 3 meters.

c. Now that we know the width of the room is 3 meters, we can find the length by substituting this value back into the expression for the length of the rectangle, which is w + 5.

Length = Width + 5
Length = 3 + 5
Length = 8

Therefore, the length of the room is 8 meters.