A flowerpot falls from a window sill 38.5 m
above the sidewalk.
What is the velocity of the flowerpot when
it strikes the ground? The acceleration of
gravity is 9.81 m/s
2
.
Answer in units of m/s.
Use v1^2-v0^2=2aS
v1=final velocity
v0=initial velocity (0 for a free-fall)
a=acceleration due to gravity (=-9.81 m/s^2)
S=-38.5m
solve for v1.
Why did the flowerpot become an astronaut? Because it reached new heights! Now, let's calculate its velocity when it strikes the ground.
To find the velocity, we can use the formula:
v = √(2gh)
Where:
v is the velocity,
g is the acceleration due to gravity, and
h is the height of the fall.
Plugging in the values:
g = 9.81 m/s²
h = 38.5 m
v = √(2 * 9.81 * 38.5)
v ≈ 24.99 m/s
So, the flowerpot's velocity when it strikes the ground is approximately 24.99 m/s. Keep an eye out for falling flowerpots, they can really "potentially" make an impact!
To find the velocity of the flowerpot when it strikes the ground, we can use the equation of motion:
v^2 = u^2 + 2as
where:
v = final velocity (unknown)
u = initial velocity (0 m/s as the flowerpot starts from rest)
a = acceleration due to gravity (-9.81 m/s^2, negative as it acts in the opposite direction of motion)
s = displacement (38.5 m)
Plugging in the values:
v^2 = 0^2 + 2*(-9.81)*38.5
v^2 = 2*(-9.81)*38.5
v^2 = -2*9.81*38.5
v^2 = -756.63
v ≈ √(-756.63) (take the square root, ignoring the negative sign since we are interested in the magnitude of the velocity)
v ≈ 27.50 m/s
Therefore, the velocity of the flowerpot when it strikes the ground is approximately 27.50 m/s.
To find the velocity of the flowerpot when it strikes the ground, we can use the equation for the final velocity of an object in free fall:
v^2 = u^2 + 2as
Where:
v = final velocity
u = initial velocity (which is 0 since the flowerpot is initially at rest)
a = acceleration due to gravity
s = displacement (height of the flowerpot above the ground)
In this case, the flowerpot falls from a height of 38.5 m, so we can substitute the values into the equation:
v^2 = 0^2 + 2 * 9.81 * 38.5
Simplifying:
v^2 = 2 * 9.81 * 38.5
v^2 = 754.73
To find v, we take the square root of both sides:
v = √754.73
v ≈ 27.48 m/s
Therefore, the velocity of the flowerpot when it strikes the ground is approximately 27.48 m/s.