A certain car is capable of accelerating at a

uniform rate of 0.83 m/s2
.
What is the magnitude of the car’s displacement
as it accelerates uniformly from a speed
of 80 km/h to one of 92 km/h?

See previous post: Fri, 9-25-15, 7:13 AM

To find the magnitude of the car's displacement, we need to calculate the change in position or distance traveled by the car as it accelerates uniformly from a speed of 80 km/h to 92 km/h.

First, we need to convert the given speeds from kilometers per hour (km/h) to meters per second (m/s) since the acceleration is given in meters per second squared (m/s^2).

Converting 80 km/h to m/s:
80 km/h = 80,000 m/3,600 s = 22.22 m/s

Converting 92 km/h to m/s:
92 km/h = 92,000 m/3,600 s = 25.56 m/s

Now, we can use the following equation to calculate the displacement:

Displacement = (final velocity squared - initial velocity squared) / (2 * acceleration)

Plugging in the values:
Displacement = (25.56^2 - 22.22^2) / (2 * 0.83)
Displacement ≈ (653.2936 - 493.7284) / (1.66)
Displacement ≈ 0.5151 m

Therefore, the magnitude of the car's displacement as it accelerates uniformly from a speed of 80 km/h to 92 km/h is approximately 0.5151 meters.