A rectangular picture frame has a perimeter of 58 inches. The height of the frame is 18 inches. What is the width of the frame? Please help show work and help answer thanks
P = 2L + 2W
58 = 2L + 2(18)
58 = 2L + 36
22 = 2L
11 = L
To find the width of the frame, we can use the formula for the perimeter of a rectangle, which is 2 times the width plus 2 times the height.
Given information:
Perimeter = 58 inches
Height = 18 inches
Let's substitute the values into the formula:
58 = 2w + 2h
Since the height is given as 18 inches, we can substitute for h:
58 = 2w + 2(18)
Now simplify the equation:
58 = 2w + 36
Subtract 36 from both sides to isolate the variable:
58 - 36 = 2w
22 = 2w
Now, divide both sides by 2 to solve for w:
22/2 = w
11 = w
Therefore, the width of the frame is 11 inches.
P = 2L + 2W
58 = 2L + 2(18)
58 = 2L + 36
22 = 2L
11 = L