Dry air has a density of 1.29g/L (at 25 degrees celsius and 1 atm of pressure). How many liters would 500.g of this air occupy?
mass = volume x density
You know mass (500g) and density (1.29 g/L), solve for volume.
To find out how many liters 500 g of dry air would occupy, we need to use the given density.
Density is defined as mass per unit volume. In this case, the density of dry air is 1.29 g/L.
We can rearrange this equation to solve for volume:
Density = Mass / Volume
Volume = Mass / Density
Plugging in the given values:
Volume = 500 g / 1.29 g/L
Volume = 387.6 L
Therefore, 500 g of dry air would occupy approximately 387.6 liters.
To calculate the volume of dry air, we need to use the given density and mass of the air sample.
The formula to calculate volume using density and mass is:
Volume = Mass / Density
Given:
Density of dry air = 1.29 g/L
Mass of dry air = 500 g
Substituting the values into the formula, we get:
Volume = 500 g / 1.29 g/L
To find the volume of 500 g of dry air, divide 500 g by 1.29 g/L.
Volume = 500 g / 1.29 g/L
Using division, we find:
Volume ≈ 387.60 L
Therefore, 500 g of dry air would occupy approximately 387.60 liters of space.