What is the pOH if the (OH-) is 1 x 10 -10 ?
Please show your work? Plug the numbers into the formula
To find the pOH, we can use the formula:
pOH = -log(OH-)
Given that the OH- concentration is 1 x 10^-10, we can substitute it into the formula:
pOH = -log(1 x 10^-10)
To evaluate this expression, we can use the logarithmic property that states:
log(a x b) = log(a) + log(b)
Therefore,
pOH = -log(1) - log(10^-10)
Since log(1) is equal to 0,
pOH = 0 - (-10) log(10)
Using another logarithmic property, log(a^b) = b * log(a), we can simplify the expression further:
pOH = 10 log(10)
Now, log(10) is equal to 1:
pOH = 10 * 1
Thus, the pOH is equal to 10.
To summarize, the pOH of a solution with an OH- concentration of 1 x 10^-10 is 10.