a student adds 3 spoons of salt to 100 ml of water. the solution is clear, with nothing on the bottom of the cup. one spoon of the slat ha a mass of 5g. what is the mass of the solution? after the water evaporates, what is the mass of the solid remaining in the cup?
If the density of the water is 1.00 g/mL, then 100 mL has a mass of 100 g. That + 3*5 = 15 g salt added make the solution's mass = 115 g. When all of the water is evaporated the mass of the salt remaining is 15 g.
To find the mass of the solution, we need to consider the mass of both the water and the salt. Here's how we can calculate it:
1. First, we need to find the total mass of the salt added. We are given that one spoon of salt has a mass of 5g. Since the student added 3 spoons of salt, the total mass of the salt added would be 5g multiplied by 3, which equals 15g.
2. Next, we need to determine the mass of the water. We are told that 100 ml of water was used. However, to convert ml (milliliters) to grams, we need to know the density of water. At room temperature, the density of water is approximately 1g/ml. So, the mass of 100 ml of water would be 100g.
3. Finally, to find the mass of the solution, we add the mass of the salt and the mass of the water together. Therefore, the mass of the solution would be 15g (salt) + 100g (water) = 115g.
Now, let's calculate the mass of the solid remaining in the cup after the water evaporates:
When the water evaporates, only the salt will remain in the cup. Therefore, the mass of the solid remaining would be equal to the initial mass of the salt added, which is 15g.