Calories to heat 8.1 g of water from 15 Celsius to 34 celsius
cal needed = mass H2O x specific heat H2O x (Tfinal-Tinitial)
8.1×22×2.03=361.746
To calculate the calories required to heat 8.1 g of water from 15°C to 34°C, we need to use the formula:
Q = m * c * ΔT
Where:
Q = energy (in calories)
m = mass of the substance (in grams)
c = specific heat capacity (in calories/gram °C)
ΔT = change in temperature (in °C)
First, let's find the specific heat capacity of water. The specific heat capacity of water is 1 calorie/gram °C.
Now, substitute the values into the equation:
Q = 8.1 g * 1 calorie/gram °C * (34°C - 15°C)
Q = 8.1 g * 1 calorie/gram °C * 19°C
Q = 154.59 calories
So, it would take approximately 154.59 calories to heat 8.1 g of water from 15°C to 34°C.