From your mass of MgNH4PO4.6H2O collected, calculate your value
a) for the mass of "P2O5" in the initial mass of fertilizer analyzed
b) the % "P2O5" in the fertilizer. Compare this with the manufacturer's specification.
Just want to know how i would go about this question, where would I start.
I responded to this in detail at your first post. You need to go back and check for answers before posting again.
To calculate the value for the mass of "P2O5" in the initial mass of the fertilizer analyzed and the percentage of "P2O5" in the fertilizer, we need to follow a series of steps. Here's how you can approach this question:
Step 1: Determine the molar mass of MgNH4PO4·6H2O.
First, find the molar masses of each element in the compound:
- Mg (Magnesium) has a molar mass of 24.31 g/mol.
- N (Nitrogen) has a molar mass of 14.01 g/mol.
- H (Hydrogen) has a molar mass of 1.01 g/mol.
- P (Phosphorus) has a molar mass of 30.97 g/mol.
- O (Oxygen) has a molar mass of 16.00 g/mol.
Add up the molar masses of all the elements present in MgNH4PO4·6H2O to get the total molar mass of the compound.
Step 2: Convert the mass of MgNH4PO4·6H2O to moles.
To do this, divide the mass of the compound by its molar mass. The molar mass can be found in the periodic table or calculated in step one.
Step 3: Calculate the molar ratio of "P2O5" to MgNH4PO4·6H2O.
From the balanced chemical equation, we know that there is a 1:1 mole ratio between "P2O5" and MgNH4PO4·6H2O. This means that for every mole of MgNH4PO4·6H2O, there is an equal amount of moles of "P2O5."
Step 4: Convert the moles of "P2O5" to grams.
Multiply the number of moles of "P2O5" by its molar mass to find its mass in grams.
Step 5: Calculate the percentage of "P2O5" in the fertilizer.
Divide the mass of "P2O5" by the initial mass of the fertilizer and then multiply by 100 to get the percentage.
Step 6: Compare the calculated percentage with the manufacturer's specification.
Check the manufacturer's specification for the percentage of "P2O5" in the fertilizer. Compare it with the calculated percentage to see if they match.
By following these steps, you should be able to determine the mass of "P2O5" in the initial mass of the fertilizer analyzed and the percentage of "P2O5" in the fertilizer.
To calculate the mass of "P2O5" in the fertilizer and the percentage of "P2O5" in the fertilizer, we can follow these steps:
Step 1: Determine the molar mass of MgNH4PO4.6H2O (magnesium ammonium phosphate hexahydrate).
The molar mass of MgNH4PO4.6H2O can be calculated by adding up the molar masses of each element present in it.
Mg: 24.31 g/mol
N: 14.01 g/mol
H: 1.01 g/mol (6 atoms in H2O)
P: 30.97 g/mol
O: 16.00 g/mol (6 atoms in H2O)
Molar mass of MgNH4PO4.6H2O = (24.31 g/mol) + (14.01 g/mol) + (1.01 g/mol × 6) + (30.97 g/mol) + (16.00 g/mol × 6) = 245.42 g/mol
Step 2: Convert the mass of MgNH4PO4.6H2O collected to moles.
Let's assume we collected "x" grams of MgNH4PO4.6H2O.
Moles of MgNH4PO4.6H2O = mass / molar mass = x g / 245.42 g/mol
Step 3: Calculate the moles of "P" in MgNH4PO4.6H2O.
There is 1 mole of "P" in 1 mole of MgNH4PO4.6H2O. Therefore, the moles of "P" can be directly derived from the moles of MgNH4PO4.6H2O.
Moles of "P" = Moles of MgNH4PO4.6H2O
Step 4: Convert the moles of "P" to the mass of "P2O5".
Using the molar mass of P2O5 (141.94 g/mol), we can convert the moles of "P" to the mass of "P2O5".
Mass of "P2O5" = Moles of "P" × Molar mass of P2O5 = Moles of "P" × 141.94 g/mol
This gives us the answer for part (a) - the mass of "P2O5" in the initial mass of the fertilizer analyzed.
Step 5: Calculate the percentage of "P2O5" in the fertilizer.
To determine the percentage of "P2O5" present in the fertilizer, divide the mass of "P2O5" by the initial mass of the fertilizer and multiply by 100.
% "P2O5" = (Mass of "P2O5" / Initial mass of fertilizer) × 100
Compare this value with the manufacturer's specification to determine if the percentage meets the specified requirements.
Note: In order to calculate the mass of "P2O5" and the percentage of "P2O5," you will need the initial mass of the collected fertilizer as well as the manufacturer's specification.