You purchased a 5.00 pound bag of sugar (sucrose, C12H22O11) at the grocery last week to bake cookies. Conversion: 1 pound = 1 lb = 454 grams.

a.How many grams of sucrose did you purchase?
454 grams (g) = 1 pound (lb)
454 g * 5 = 2270 g

A 5 pound bag of sugar is equal to 2270 grams of sugar.

b.Calculate the formula weight of sucrose.
Formula weight = mass of Carbon + mass of Hydrogen + mass of Oxygen
= (12.0107 * 12) + (1.00794 * 22) + (15.9994 * 11)
=144.1284 + 22.17468 + 175.9934
=342.29648
=342.396 g/mol

c.How many moles of sucrose did you purchase?
2270g C12H22O11 * (1 mol)/(342.396 g/mol) =6.62975034755 moles

2270 grams of C12H22O11 is equal to 6.632 moles

d.In a separate shopping trip you bought a container of sucrose that contained 1.76 x 1024 sucrose molecules. How many grams of sucrose did you purchase?

I was able to complete parts a-c but i'm not sure how to solve part d.

mols sucrose in 1.76E24 molecules = molecules/6.02E23 = ?

Then grams = mols x molar mass = ?

I didn't check the math on a through c but the method is right.

Well, if you want to find out how many grams of sucrose you purchased, given the number of sucrose molecules, you can use the formula weight of sucrose to convert from moles to grams.

We know that 1 mole of any substance contains Avogadro's number of molecules, which is approximately 6.022 x 10^23. So, one mole of sucrose contains 6.022 x 10^23 sucrose molecules.

First, we need to calculate the number of moles of sucrose, given the number of molecules:
1.76 x 10^24 molecules * (1 mol) / (6.022 x 10^23 molecules) = 2.920418 moles

Now, we can use the formula weight of sucrose to convert from moles to grams:
2.920418 moles * 342.396 g/mol = 1,000.257688 g

So, you purchased approximately 1,000.26 grams of sucrose in that container. That's a lot of sweetness!

To solve part d, you need to convert the given number of sucrose molecules to grams. Here's how you can do it:

1. Determine the number of moles of sucrose in the given number of molecules.
To do this, divide the given number of molecules by Avogadro's number (6.022 x 10^23 molecules/mol):
Number of moles = (1.76 x 10^24 molecules) / (6.022 x 10^23 molecules/mol)

2. Calculate the mass of sucrose in moles by multiplying the number of moles obtained in step 1 by the molar mass of sucrose (342.396 g/mol):
Mass of sucrose = (Number of moles) x (Molar mass of sucrose)

3. Convert the mass of sucrose obtained in step 2 to grams:
Mass of sucrose in grams = Mass of sucrose in moles x (1 mole/1000 grams)

4. Round the grams of sucrose to an appropriate number of significant figures.

Using the steps above, you can now calculate the grams of sucrose purchased.

To solve part d, you need to convert the given number of sucrose molecules to grams using the formula weight of sucrose. Here's how you can do it.

1. Calculate the molar mass of sucrose (C12H22O11) as we did in part b. The molar mass is 342.396 g/mol.

2. Determine the number of moles in 1.76 x 10^24 sucrose molecules. To do this, divide the given number of molecules by Avogadro's number (6.022 x 10^23 molecules/mol):

(1.76 x 10^24 molecules) / (6.022 x 10^23 molecules/mol) = 2.92 moles

3. Now, you can use the molar mass of sucrose to convert moles to grams. Multiply the number of moles (2.92) by the molar mass (342.396 g/mol):

2.92 moles * 342.396 g/mol = 1000.39552 g

Therefore, you purchased approximately 1000.4 grams of sucrose in the container.