haby is four times as old as kenneth and
haby is 36 years older than kenneth . how old is haby.
h = 4k
h - k = 36
Substitute 4k for h in the second equation and solve for k. Insert that value into the first equation to solve for h. Check by putting both values into the second equation.
Let's assume Kenneth's age is X.
According to the given information, Haby is four times as old as Kenneth, so Haby's age would be 4X.
It is also mentioned that Haby is 36 years older than Kenneth, so we can write the equation: 4X = X + 36.
Simplifying the equation, we get: 3X = 36.
Dividing both sides by 3, we find: X = 12.
Therefore, Kenneth is 12 years old.
To find Haby's age, we substitute X back into the equation: Haby's age = 4 * 12 = 48.
So, Haby is 48 years old.
To find the age of Haby, we can use algebraic equations. Let's represent Kenneth's age as 'K' and Haby's age as 'H'.
Given that Haby is four times as old as Kenneth, we can write the equation: H = 4K.
Also given that Haby is 36 years older than Kenneth, we can write the equation: H = K + 36.
Since we have two equations as shown above, we can solve them simultaneously to find the age of Haby.
Substituting the value of H from the first equation into the second equation: 4K = K + 36.
Solving this equation: 4K - K = 36, which simplifies to 3K = 36.
Next, divide both sides of the equation by 3: K = 36 / 3 = 12.
Now that we know Kenneth's age is 12, substitute this value back into the first equation to find Haby's age: H = 4 * 12 = 48.
Therefore, Haby is 48 years old.