A hose lying on the ground shoots a stream of water upward at an angle of 60deg. To the horizontal with a velocity of 16m/s . The height at which the water strikes the wall 8m away is?
this answer is wrong
the correct answer is 14.64m
To find the height at which the water strikes the wall, we can break down the given information into its vertical and horizontal components.
First, we need to find the time it takes for the water to travel 8m horizontally. We can use the horizontal component of the velocity and the distance to calculate this time.
Horizontal component of velocity = velocity * cos(angle)
= 16 m/s * cos(60°)
= 16 m/s * 1/2
= 8 m/s
Time taken = distance / horizontal component of velocity
= 8 m / 8 m/s
= 1 s
Now, let's analyze the vertical motion of the water. We know the initial vertical velocity is given by the vertical component of the velocity.
Vertical component of velocity = velocity * sin(angle)
= 16 m/s * sin(60°)
= 16 m/s * √3/2
= 8√3 m/s
Using this initial vertical velocity, we can calculate the height at which the water strikes the wall using the equation:
height = (initial vertical velocity * time) - (0.5 * acceleration due to gravity * time^2)
Since the water is going upwards, the acceleration due to gravity is negative.
height = (8√3 m/s * 1 s) - (0.5 * 9.8 m/s^2 * (1 s)^2)
= 8√3 m - 4.9 m
= (8√3 - 4.9) m
Therefore, the height at which the water strikes the wall 8m away is approximately (8√3 - 4.9) meters.
U is equal to 8 root 3
this answer is wrong
the correct answer is 14.64m
horizontal problem:
u = 16 cos 60 = 8 m/s
t = d/u = 8/8 = 1 second
Vi = 16 sin 60 = 13.9 m/s
h = Vi t - 4.9 t^2
h = 13.9 (1) - 4.9 (1)^2
h = 9 m