Part 1:

Find the % by mass of each element in camphor (C10H20O).

Step 1: Find the atomic mass of each element in the molecule.
Atomic Mass of C: 12.0107
Atomic Mass of H: 1.00794
Atomic Mass of O: 15.9994

Step 2: Find the mass combination of each element.
Carbon: 10 atoms 10 * 12.0107 = 120.107 g/mol
Hydrogen: 20 atoms 20 * 1.00794 = 20.1588 g/mol
Oxygen: 1 atom 1 * 15.9994 = 15.9994 g/mol

Step 3: Find the total molecular mass of the molecule.
Molecular Mass of (C10H20O) = 120.107 g/mol + 20.1588 g/mol + 15.9994 g/mol = 156.2652 g/mol

Step 4: Find the mass percent composition of each element.
Mass percent composition of C=(Mass Contribution of C)/(Molecular Mass ofC10H20O)*100%
=(120.107 g/mol)/(156.2652 g/mol)*100%
=0.76861002961 * 100%
=76.86%

Mass percent composition of H=(Mass Contribution of H)/(Molecular Mass ofC10H20O)*100%
=(20.1588 g/mol)/(156.2652 g/mol)*100%
=0.12900377051 * 100%
=12.90%

Mass percent composition of O=(Mass Contribution of O)/(Molecular Mass ofC10H20O)*100%
=(15.9994 g/mol)/(156.2652 g/mol)*100%
=0.10238619987 * 100%
=10.24%

%C = 76.86%
%H =12.90%
%O = 10.24%

Part 2
What is the mass of oxygen (in grams) present in 1.0 pound (454 grams) of camphor?

I was able to answer all of part 1 but I am not sure how to continue and answer part 2.

You have 454 g camphor.

mass %O in camphor is 10.24% so
454 x 0.1024 = ? g O

Oh, so you want to know the mass of oxygen in 1.0 pound of camphor? Well, let's get cracking!

We know that the percent composition of oxygen in camphor is 10.24%. So, to find the mass of oxygen in 1.0 pound of camphor, we can use the equation:

Mass of Oxygen = Percent Composition of Oxygen * Total Mass of Camphor

Since 1 pound is equal to 454 grams, we can substitute this value into the equation:

Mass of Oxygen = 10.24% * 454 grams

Now, let's do the math!

Mass of Oxygen = 0.1024 * 454 grams

*clown-bot takes out a calculator*

Hmm...let me crunch these numbers for you...

*clown-bot starts banging on the calculator*

Okay, okay...I've got the answer! The mass of oxygen in 1.0 pound (454 grams) of camphor is approximately 46.46 grams.

So there you have it! Oxygen is a pretty substantial part of camphor, weighing in at 46.46 grams in a 1.0 pound sample.

To find the mass of oxygen present in 1.0 pound (454 grams) of camphor, you can use the percent composition calculated in Part 1.

Step 1: Convert the percent composition of oxygen to decimal form.
Mass percent composition of O = 10.24%
10.24% = 0.1024

Step 2: Multiply the decimal mass percent composition of oxygen by the total mass of 1.0 pound (454 grams) of camphor.
Mass of oxygen = 0.1024 * 454 grams
= 46.4896 grams

Therefore, the mass of oxygen present in 1.0 pound (454 grams) of camphor is approximately 46.49 grams.

To answer part 2, you need to use the mass percent composition of the elements in camphor and the given mass of camphor to find the mass of oxygen present. Here's how you can do it:

Step 1: Calculate the mass of oxygen in 1.0-pound (454 grams) of camphor using the mass percent composition of oxygen in camphor.

Mass of Oxygen = (Mass percent composition of O/100) * Mass of camphor

Mass of Oxygen = (10.24/100) * 454 grams

Mass of Oxygen = 0.1024 * 454 grams

Mass of Oxygen = 46.57 grams

Therefore, the mass of oxygen present in 1.0 pound (454 grams) of camphor is 46.57 grams.