Imagine that you have a stock solution with a concentration of 4.6 M glucose (C1).
You want to use the stock solution to prepare a diluted solution of 0.22M glucose (C2).
You need a total volume of 10mL of 0.22M glucose (V2).
What volume of water you need to use for making 0.22M glucose? Express your answer in mL
I got 478.26
The other I couldn't figure out... I'm not sure how to distinguish between the two.
Imagine that you have a stock solution with a concentration of 4.6 M glucose (C1).
You want to use the stock solution to prepare a diluted solution of 0.22M glucose (C2).
You need a total volume of 10mL of 0.22M glucose (V2).
What volume of the stock solution would you need to use for making 0.22M glucose? Express your answer in mL.
To determine the volume of water needed to make a diluted solution of 0.22 M glucose (C2), you can use the equation:
C1V1 = C2V2
In this case, C1 = 4.6 M, C2 = 0.22 M, V2 = 10 mL, and we need to find V1 (volume of water).
Rearranging the equation, we get:
V1 = (C2V2) / C1
Plugging in the values:
V1 = (0.22 M * 10 mL) / 4.6 M
= 2.2 mL / 4.6
≈ 0.478 mL
Therefore, you need to use approximately 0.478 mL of water to make the 0.22 M glucose solution with a total volume of 10 mL.
For the second question, to determine the volume of the stock solution (C1) needed to make 0.22 M glucose (C2), we can use the same equation:
C1V1 = C2V2
In this case, C1 = ?, C2 = 0.22 M, V2 = 10 mL, and we need to find V1 (volume of the stock solution).
Rearranging the equation, we get:
V1 = (C2V2) / C1
Plugging in the values, we have:
V1 = (0.22 M * 10 mL) / C1
Since C1 is the unknown, we cannot determine the exact volume of the stock solution needed without knowing C1.