ten-pin bowling ball has a volume of about 5274 cm3. A candlepin (8) bowling ball has a volume of about 48 in3. About how much greater is the volume

of a ten-pin bowling ball than the volume of a candlepin bowling ball?

smaller ball:

48 in^3 = (2.54^3)(48) cm^3 , (since 1 inch = 2.54 cm)
= 786.579 cm^3

ratio of volumes = 5274/786.579 = 6.7

so the 10-pin ball is about 6.7 times the volume of the smaller ball

To find out how much greater the volume of a ten-pin bowling ball is compared to a candlepin bowling ball, we first need to convert the volume of each ball to the same unit. Let's convert the volume of the ten-pin bowling ball from cm³ to in³.

1 cm³ is equal to 0.0610237 in³. Multiplying the volume of the ten-pin bowling ball (5274 cm³) by the conversion factor, we get:

Volume in in³ = 5274 cm³ * 0.0610237 in³/cm³ ≈ 322 in³.

Now that we have both volumes in the same unit (in³), we can calculate the difference:

Difference in volume = Volume of ten-pin ball - Volume of candlepin ball
= 322 in³ - 48 in³
≈ 274 in³.

Therefore, the volume of a ten-pin bowling ball is about 274 in³ greater than the volume of a candlepin bowling ball.