Formulate a problem and spolution of the diameter ofvthe atomic nucleus of a lead atom is 1.75 X 10 to the negative 15th meter.
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Online, “*” is used to indicate multiplication to avoid confusion with “x” as an unknown.
1.75*10^-15
Problem: Determining the diameter of the atomic nucleus of a lead atom given its size.
Solution:
To solve this problem, we can use the given information and the formula for the diameter of a sphere to find the nucleus' diameter.
The formula for the diameter of a sphere is given by:
Diameter = 2 * Radius
We are given the diameter of the atomic nucleus, which is 1.75 x 10^(-15) meters. The radius can be found by dividing the diameter by 2:
Radius = Diameter / 2 = (1.75 x 10^(-15)) / 2
The next step is to evaluate this expression.
1.75 x 10^(-15) / 2 = 8.75 x 10^(-16) meters
Therefore, the radius of the atomic nucleus of a lead atom is 8.75 x 10^(-16) meters.
Note: The solution assumes a simplified model of the atomic nucleus as a sphere, disregarding the non-uniform distribution of subatomic particles within it.