Logarithm help
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Logarithm help
using logarithms to solve exponential equations. 5^1+x = 2^1x I need exact numbers. I did one on my own already. 5^x1 = 9 5^x1 = 9 log(5^x1) = log9 (log5)(x1) = log9 x1 = (log9/log5) x= (log9/log5)1 x = 2.3652 
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