The man gave 1/2 of his money to his brother,1/6to his friend and the remainder an amount of P150,000 which he kept.How much money does the man originally have?
original --- x
x - x/2 - x/6 = 150000
times 6
6x - 3x - x = 900000
2x=900000
x = 450000
To find out how much money the man originally had, we can add up the amounts he gave away to his brother and friend, and then add the amount he kept for himself.
Let's break it down step by step:
1. The man gave away 1/2 of his money to his brother. This means he kept 1/2 of his money for himself.
2. He also gave away 1/6 of his money to his friend. This means he kept 5/6 of his money for himself.
3. The amount he kept for himself is P150,000.
Now, let's calculate how much money the man originally had using the information above:
1. Since he kept 5/6 of his money, the amount he kept is equal to 5/6 of his original amount.
So, we can set up the equation: 5/6 * x = 150,000, where x is his original amount of money.
2. To solve for x, we can multiply both sides of the equation by 6/5 (the reciprocal of 5/6) to isolate x.
6/5 * (5/6 * x) = 6/5 * 150,000
x = 180,000
Therefore, the man originally had P180,000.