At the party Jade ate less than four jelly beans. Nicole ate twice as many jelly beans as Jade. Kahlee had twice as many as Nicole. Chris had two more than kahlee. Chris ate ten jelly beans. How many jelly beans were eaten at the party?

Chris, 10

Kahlee, 10 – 2 = 8
Nicole, 8 ÷ 2 = 4
Jane, 4 ÷ 2 = 2
Total jelly beans eaten = 2 + 4 + 8 + 10 = 24.

To find out how many jelly beans were eaten at the party, we need to add up the number of jelly beans each person ate.

Let's first find out how many jelly beans Kahlee had. We know that Chris had two more than Kahlee, and Chris ate ten jelly beans. So, Kahlee must have had 10 - 2 = <<10-2=8>>8 jelly beans.

Next, we know that Kahlee had twice as many jelly beans as Nicole. Since Nicole ate twice as many jelly beans as Jade, we can conclude that Nicole ate 2 * (less than 4 jelly beans). Since it says "less than" four jelly beans, let's consider Nicole ate 3 jelly beans.

Now, we can calculate Kahlee's jelly beans as Kahlee had twice as many as Nicole, i.e., 2 * 3 = <<2*3=6>>6 jelly beans.

Finally, we can calculate the total number of jelly beans eaten at the party by adding up the jelly beans each person ate: Jade (less than 4) + Nicole (3) + Kahlee (6) + Chris (10) = (less than 4) + 3 + 6 + 10 = (less than 4 + 3 + 6 + 10).

Since we don't have the exact number of jelly beans Jade ate, we cannot determine the total number of jelly beans eaten at the party precisely. We can only say that it is less than 4 + 3 + 6 + 10 = 23 jelly beans.

its actually 24

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Jk it’s 38?

I think 38 because jade ate 4. Nicole ate 8. Kahlee ate 16. And Chris ate 10. Add them all up and you get 38.