Two hikers are climbing up a mountain and one throws a first aid kit up to another at an initial velocity of 11 m/s and at an angle of 62 deg above the horizontal. At the moment it is caught, the vertical speed is zero. What is the difference in height between the two climbers?
I'm not really sure where to start.
I tried doing 6.17sin(62) = 5.45 to find the height and that was wrong.
Vi = 11 sin 62
V = Vi - 9.81 t
at top V = 0
so t = Vi/9.81
h = Vi t - 4.9 t^2