Calculate the number of moles of carbon
atoms present in 1.1 g of ethanol (C2H6O).
Answer in units of mol.
.5 moles of c
To calculate the number of moles of carbon atoms in 1.1 g of ethanol (C2H6O), we need to follow a few steps:
Step 1: Find the molar mass of ethanol (C2H6O).
The molar mass is the sum of the atomic masses of all the atoms in a molecule. The atomic masses of carbon (C), hydrogen (H), and oxygen (O) are approximately 12 g/mol, 1 g/mol, and 16 g/mol, respectively.
Molar mass of C2H6O = 2 * atomic mass of carbon + 6 * atomic mass of hydrogen + atomic mass of oxygen
= 2 * 12 g/mol + 6 * 1 g/mol + 16 g/mol
= 24 g/mol + 6 g/mol + 16 g/mol
= 46 g/mol
Step 2: Convert the given mass of ethanol to moles.
We can use the formula:
Number of moles = given mass / molar mass
Number of moles of ethanol = 1.1 g / 46 g/mol
≈ 0.02391 mol
Step 3: Calculate the number of moles of carbon atoms.
Since there are two carbon atoms in one molecule of ethanol, the number of moles of carbon atoms will be twice the number of moles of ethanol.
Number of moles of carbon atoms = 2 * number of moles of ethanol
= 2 * 0.02391 mol
= 0.04782 mol
Therefore, there are approximately 0.04782 moles of carbon atoms present in 1.1 g of ethanol (C2H6O).
mols C2H6O = grams/molar mass = ?
mols C atoms is twice that since there are two mols C atoms/mol C2H6O.