Login or Sign Up

Ask a New Question

1. What volume of nitric acid solution with mass fraction of 16% is required to make make 250ml solution with 0.2mole/l?

Don't you need the density of the HNO3 to get the volume?

Similar Questions

Students are instructed to add no more than 0.25 mL of 15 M nitric acid. Whatvolume of 15 M nitric acid is required to react

Top answer: you have to first calculate the moles of the copper, then 0.03/63.01 then afterwards times it by Read more.
An aqueous solution of nitric acid is standardized by titration with a 0.121 M solution of calcium hydroxide.If 24.5 mL of base

Top answer: 54 Read more.
A solution containing nitric acid (HNO3) is to be used in the neutralization titration of a sodium hydroxide (NaOH) solution.a.

Top answer: a. pH = -log(HNO3) 2.30 -log(HNO3) (HNO3) = ? in moles/L which is the same as equivalents/L = Read more.
I have a .283M of Nitric acid in 5500 kg of water. How much of 68% Nitric acid do I need to add to make the nitric acid solution

Top answer: Is this molarity (M) or molality (m). If M what is the density of the 0.283 M solution. Read more.
1000 g of a 50% (mass percentage) nitric acid solution is to be diluted to 20%(mass percentage) nitric acid solution. How many

Top answer: The dilution formula works as well for percent by mass as it does for molarity and normality. %1 x Read more.
1000 g of a 50% (mass percentage) nitric acid solution is to be diluted to 20%(mass percentage) nitric acid solution. How many

Top answer: 1.55 liters Read more.
1000g of a 50%(mass percentage) nitric acid solution is to be dil ute to 20%(mass percentage) nitric acid solution.how many lit

Top answer: Use the dilution formula. %1 x soln1 = %2 x soln2 Read more.
A nitric acid solution at 25% by weight has a density of 1.21 KG / L Calculate the volume needed to be taken to obtain 2 L of a

Top answer: To calculate the volume of the 25% nitric acid solution needed to obtain 2 L of a 2.5 M solution, we Read more.
Two acid solutions are available to a chemist. One is 10% nitric acid solution, the other is 4% nitric acid solution. How much

Top answer: Ix x ml of 10%, then the rest (600-x) is 4%. So, .10(x) + .04(600-x) = .06(600) Read more.
A nitric acid solution containing 71.0% by mass of the acid has a density of 1.42g/ml how many grams of nitric acid are present

Top answer: mass=.71*1.42kg/L*1L Read more.