A 2 kg body and 3 kg body are moving along x-axis .At a particular instant ,the 2 kg body has a velocity of 3 m per sec and the 3 kg body has the velocity of 2 m per sec . The velocity of the center of mass at that instant is.
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M1(v1)+M2(v2)÷M2+M1=12/5=2.4
To find the velocity of the center of mass, we need to use the principle of conservation of momentum.
The formula to calculate the velocity of the center of mass is:
vcm = (m1v1 + m2v2) / (m1 + m2)
where:
vcm is the velocity of the center of mass
m1 and m2 are the masses of the two bodies
v1 and v2 are the velocities of the two bodies
Given:
m1 = 2 kg
v1 = 3 m/s
m2 = 3 kg
v2 = 2 m/s
Using the formula, we can substitute the given values:
vcm = (2 kg * 3 m/s + 3 kg * 2 m/s) / (2 kg + 3 kg)
Simplifying the equation:
vcm = (6 kg·m/s + 6 kg·m/s) / 5 kg
vcm = 12 kg·m/s / 5 kg
vcm = 2.4 m/s
Therefore, the velocity of the center of mass at that instant is 2.4 m/s.