The coordinates of the vertices of ABC are A(-2,2) B (5, -3) and C (-4,-1) Identify the perimeter of ABC. Round each length to the nearest tenth before adding.

I am totally lost!

find the perimeter of the figure with the given vertices. round to the nearest tenth. D(0,1), E(5,4), and F(2,6)

To find the perimeter of triangle ABC, you'll need to calculate the lengths of each side. The formula for finding the distance between two points (x1, y1) and (x2, y2) is given by:

Distance = √((x2 - x1)^2 + (y2 - y1)^2)

Let's calculate the lengths of each side:

Side AB:
Distance = √((5 - (-2))^2 + (-3 - 2)^2)
= √((7)^2 + (-5)^2)
= √(49 + 25)
= √(74)
≈ 8.6 (rounded to the nearest tenth)

Side BC:
Distance = √((-4 - 5)^2 + (-1 - (-3))^2)
= √((-9)^2 + (2)^2)
= √(81 + 4)
= √(85)
≈ 9.2 (rounded to the nearest tenth)

Side AC:
Distance = √((-4 - (-2))^2 + (-1 - 2)^2)
= √((-2)^2 + (-3)^2)
= √(4 + 9)
= √(13)
≈ 3.6 (rounded to the nearest tenth)

Now, to find the perimeter, you add up the three side lengths:

Perimeter = AB + BC + AC
≈ 8.6 + 9.2 + 3.6
≈ 21.4 (rounded to the nearest tenth)

Therefore, the perimeter of triangle ABC is approximately 21.4 units.

To find the perimeter of triangle ABC, you need to find the lengths of its three sides and then add them together.

To find the length of a side of a triangle, you can use the distance formula, which is:

d = √((x2 - x1)^2 + (y2 - y1)^2)

Let's go step by step:

1. Start with the coordinates of point A (-2, 2) and point B (5, -3). Apply the distance formula to find the distance between A and B:
d(AB) = √((5 - (-2))^2 + (-3 - 2)^2)

Simplifying further,
d(AB) = √((7)^2 + (-5)^2)
= √(49 + 25)
= √(74)
≈ 8.6 (rounded to the nearest tenth)

2. Now, find the distance between point B (5, -3) and point C (-4, -1):
d(BC) = √((-4 - 5)^2 + (-1 - (-3))^2)

Simplifying further,
d(BC) = √((-9)^2 + (2)^2)
= √(81 + 4)
= √(85)
≈ 9.2 (rounded to the nearest tenth)

3. Finally, find the distance between point C (-4, -1) and point A (-2, 2):
d(CA) = √((-2 - (-4))^2 + (2 - (-1))^2)

Simplifying further,
d(CA) = √((2)^2 + (3)^2)
= √(4 + 9)
= √(13)
≈ 3.6 (rounded to the nearest tenth)

4. Now, add the three side lengths together to find the perimeter:
Perimeter = d(AB) + d(BC) + d(CA)
≈ 8.6 + 9.2 + 3.6
≈ 21.4 (rounded to the nearest tenth)

Therefore, the perimeter of triangle ABC is approximately 21.4.

Review your length formula. Find the lengths of the sides, and add them up. I'll give you one side, you do the other two.

AB = √((5-(-2))^2+(-3-2)^2) = √(7^2+5^2) = √74