Calculate the number of moles of carbon
atoms present in 2.2 g of ethanol (C2H6O).
For this question, I would just need to find the molar mass of carbon, right? Not the molar mass of all of ethanol? So it would just be 2.2 g/ 24.02 g/mol which would equal .092. It wouldn't be 2.2 g/ 46.08 g/mol because it's only asking for carbon, right? I just want to make sure I am doing this problem correctly.
It's neither of your proposals.
It's mols ethanol = 2.2/46.08 = ?
Then mols C = 2*mols ethanol.
You're correct that you only need to find the number of moles of carbon atoms present in 2.2 g of ethanol (C2H6O). In this case, you would calculate the number of moles of carbon by dividing the mass of carbon by its molar mass.
The molar mass of carbon (C) is approximately 12.01 g/mol, not 24.02 g/mol. This is because carbon has an atomic mass of 12.01 amu.
Therefore, the calculation would be:
Number of moles of carbon = Mass of carbon / Molar mass of carbon
Number of moles of carbon = 2.2 g / 12.01 g/mol
Number of moles of carbon ≈ 0.183 mol
So, there are approximately 0.183 moles of carbon atoms present in 2.2 g of ethanol.
Yes, you are on the right track! To calculate the number of moles of carbon atoms present in 2.2 g of ethanol (C2H6O), you would indeed only need to consider the molar mass of carbon.
The molar mass of carbon (C) is approximately 12.01 g/mol, so you would divide 2.2 g by 12.01 g/mol:
2.2 g / 12.01 g/mol ≈ 0.183 moles
Therefore, there are approximately 0.183 moles of carbon atoms present in 2.2 g of ethanol (C2H6O).
It is important to note that the molar mass of carbon, and not the molar mass of the entire ethanol molecule, is used in this calculation, since you are specifically interested in the number of moles of carbon atoms.