A student throws a water balloon vertically downward from the top of a building. The balloon leaves the thrower's hand with a speed of 15.5

What is its speed after falling for 2.80 ?

How far does it fall in 2.80 ?

What is the magnitude of its velocity after falling 10.6 ?

Vector points to the north and has length A. Vector points to the east and has length B = 2.0A. Find the magnitude of in terms of A.

To solve these problems, we can use the equations of motion for freefall.

1. To find the speed of the water balloon after falling for 2.80 seconds, we can use the equation of motion:

v = u + at,

where v is the final velocity, u is the initial velocity, a is the acceleration due to gravity (-9.8 m/s²), and t is the time.

Given:
u = 15.5 m/s (initial velocity)
t = 2.80 s (time)

Using the equation, substitute the given values:

v = 15.5 m/s + (-9.8 m/s²)(2.80 s)
v = 15.5 m/s - 27.44 m/s
v = -11.94 m/s

The speed of the water balloon after falling for 2.80 seconds is 11.94 m/s downward.

2. To calculate the distance the water balloon falls in 2.80 seconds, we can use the equation of motion:

s = ut + (1/2)at²,

where s is the distance, u is the initial velocity, a is the acceleration due to gravity (-9.8 m/s²), and t is the time.

Given:
u = 15.5 m/s (initial velocity)
t = 2.80 s (time)

Using the equation, substitute the given values:

s = (15.5 m/s)(2.80 s) + (1/2)(-9.8 m/s²)(2.80 s)²
s = 43.4 m - 38.81 m
s = 4.59 m

The water balloon falls a distance of 4.59 meters in 2.80 seconds.

3. To find the magnitude of the velocity of the water balloon after falling for 10.6 seconds, we can use the equation of motion:

v = u + at,

where v is the final velocity, u is the initial velocity, a is the acceleration due to gravity (-9.8 m/s²), and t is the time.

Given:
u = 15.5 m/s (initial velocity)
t = 10.6 s (time)

Using the equation, substitute the given values:

v = 15.5 m/s + (-9.8 m/s²)(10.6 s)
v = 15.5 m/s - 103.88 m/s
v = -88.38 m/s

The magnitude of the velocity of the water balloon after falling for 10.6 seconds is 88.38 m/s downward.