What is the order of the reaction for the following reaction and for each reagent given?
A + 2B + C --> productions
Experiment / A / B / C / rate
1 / 0.002 / 0.15 / 0.132 / 0.0057
2 / 0.002 / 0.25 / 0.132 / 0.0158
3 / 0.003 / 0.15 / 0.132 / 0.0114
4 / 0.003 / 0.15 / 0.264 / 0.0114
Here is how you do the B.
Find a set where the only change is to B. That is set 1 and set 2. A is the same concentration, B is different, C is same.
So rate = k(A)^x*(B)^y*(C)^z
Since A and C are the same we can eliminate those (and k is the same so that is eliminated also).
Divide rate 2/rate 1 to get
0.0158/0.0057 = (0.25/0.15)^y and solve for y.
2.77 = (1.667)^y.
log 2.77 = y*log 1.667
0.442/0.222 = 1.99 which rounds to 2 so the exponent for B is 2.
Find x and z the same way. For order for the reaction it is x+y+z = overall order. Post your work if you get stuck.