Math

At present, the sum of the ages of a father and his son is 33 years. Determine the smallest number of years until the father's age is 4 times the son's age.

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  1. f+s=33
    f+x = 4(s+x)

    clearly, f > 4x now, since f/s decreases as both grow
    So, f > 24, meaning s < 7

    You want f to be close to 4s now, so try

    s=6, f=27
    In one year, s=7, f=28
    Looks like 1 is the smallest value.

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  2. Thank you, Steve

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