# Maths urgent

One regular polygon has twice as many sides as another. If the ratio of the interior angles of the first to that of second is 5:4, find the number of sides in each polygon?

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1. the interior angles of an n-gon are

(n-2)(180)/n

So, you have

((2n-2)/(2n)) / ((n-2)/n) = 5/4

Now just solve for n.

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posted by Steve

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