Maths urgent

One regular polygon has twice as many sides as another. If the ratio of the interior angles of the first to that of second is 5:4, find the number of sides in each polygon?

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  1. the interior angles of an n-gon are

    (n-2)(180)/n

    So, you have

    ((2n-2)/(2n)) / ((n-2)/n) = 5/4

    Now just solve for n.

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    posted by Steve

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